A major leaguer hits a baseball so that it leaves the bat at a speed of...

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A major leaguer hits a baseball so that it leaves the bat at a speed of 32.9 m/s and at an angle of 36.9° above the horizonta

Part A At what two times is the baseball at a height of 11.0 m above the point at which it left the bat? Give your answers in

Part C Calculate the vertical component of the baseballs velocity at an earlier time calculated in part (a). + VO AED o ? Vy

Part E Calculate the vertical component of the baseballs velocity at a later time calculated in part (a). ΟΙ ΑΣΦ ? Vy = m/s

Part G What is the direction of the baseballs velocity when it returns to the level at which it left the bat? IVO AO ? @= •

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Answer 1

Answer #1

HE = 32.4 Co S36-9 velocity is Klose SAVIV =U Cose Sanitat consider verticals only His usinet agt? lll - 32:9 Sin 36-9 t.- 4x please keep the number question at a time.

Projecting and landing velocity will be equal in magnitude. So landing velocity is 32.9m/s

For finding angle take

tan^-1(vertical velocity ÷ horizontal velocity)

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Answer 2

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