The Elementary Electric Charge Data: Minitial (g): 19.527g Mfinal (g): 19.161g AM(g): 0.366g I(A): 0.320A t(s):...
how do i solve for % error, by comparison with 1.602 x 10^-19? 1.6581x10-19 Data: Ministar (g): 19.5273, Mrinal (8): 19.16079 AM (g): 0.36669 I(A): 0,32 A t(s): 3600 Results: 1.6581 x 10-19 e (C/electron): %error, by comparison with 1.602 x 10-1°C: alom 63.55 с # of cu. (0.3666)(6.022x103) 3.4739 x 1021 # of transported e- 2x (3.4734 x 10") 6.9478x102 transported chrge (0.32A) (3600) 1152 1152 6.9478 x 1021
This is lab information using copper plates and an electric field. The M is the mass of the copper. The I is the amps that ran through after an hour. MInitial (g): 19.5273 g MFinal (g): 19.1607 g Mass Difference (g): .3666 I (A): .32 t (s): 3600 s (1 hour) Find the elementary charge e (C/electrons)
(9%) Problem S: An electron (n-9. 109 × 10.31kg) is in the presence of a constant electric field E. The electron has a charge of e- 1.602 x 10-19 C and it accelerates at a rate of a 8400 m/s Potential 100% #01 1602 × 10-19 C and t at a rate of a = 8400 ms Potential 0% per attempt) atan0 acotan0sinh0 (9%) Problem 8: An electron (m 1.602 x 10-19 C and it 9.109 10-31 kg) is in...
Problem 3 - Electric force and Electric field A charge Q1 = +9uC is located at the origin and a second charge Q2 = -4°C is placed at x = 8 m. a) [6 points) What will be the force (magnitude and direction) if you place a +16 C charge midway between the Qi and Q2? lu = 10-6, Coulomb's constant k = 9.0 x 10°N • m2/C2 b) [7 points] Calculate the net electric field (magnitude and direction) at...
Fundamental Constants: Elementary charge e = 1.602 × 10- C Mass of proton mp = 1.673 × 10-27 kg Mass of electron ln,-9.109 × 10-31 kg 1 . Point charges qí 7.00 μC, q,-+2.00 pC and q,--4.00 μC are fixed at locations = (0.250 + 0.433) m, = (0.000 + 0.000) m and尋= (0.500 + 0.000) m. What is the resultant vector force exerted on qi? 2. A proton is suspended in the air by an electric field at the...
A particle with mass m = 9.6 x 10-26 kg and electric charge with q = 20 *1.602 x 10-19 C moves through a region with B = -0.4 ax + 0.2 ay -0.1 az T and a velocity u = (2 ax - 3 ay +6 az) 104 m/s att = 0. 1. What electric field E must be present at = 0 if the net force F on the charged particle is 0? (7 points) 2. If the...
An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C. A) what is the change in electric potential if the election moves 1cm in the direction of the electric field? B)What is the change in electric potential energy if the electron moves 1 cm in the direction of the electric field?C) What is the change in electric potential if the election is 1 cm perpendicular to the electric field?D) What is the change in...
An electron (mass 9.11×10^-31 kg, charge -1.602×10^ -19 C)is placed in a uniform electric field, E=5000N/C. A) what is the change in electric potential if the election moves 1cm in the direction of the electric field? B)What is the change in electric potential energy if the electron moves 1 cm in the direction of the electric field?C) What is the change in electric potential if the election is 1 cm perpendicular to the electric field?D) What is the change in...
Test Ch.111 Physics 152b V =6.63 x 10-34 Js T: Choose 2 from 1.) ne = 9.109 x 10 OUR WORK! kg 8.987 x 10 Nm-/C2 electron charge mp - 1.67 x 1027 kg 1.602 x 10°C s c-3.0 x 10 m/ h mp -1.67 x 10-27 Charge = 1.602 x 10-1°C -3.0 x 10 m/s En = 8.85 x 10-12 C/Nm? Ho 4 x 1 107Tm/A le hydrogen atom is 0.51 x 10-10 m. What is the electric field...
An electric field can be created by a single charge or a distribution of charges. The electric field a distance from a point charge has magnitude E = k|q'|/r^2. The electric field points away from positive charges and toward negative charges. A distribution of charges creates an electric field that can be found by taking the vector sum of the fields created by individual point charges. Note that if a charge is placed in an electric field created by q',...