man purchase a new home with $310000
Down payment = $150000
Mortgage amount = 310000 – 150000 = 160000
Mortgage amount = $160000
Total term = 12 years
Rate of interest = 8% = 8/100 = 0.08
Compounding frequency = semi annually = 2
Now we can use the below formula to find the payment (PMT)
PMT = [ P x (r/n) x (1+(r/n)nt ] / [(1+(r/n))nt -1]
P = principal amount = $160000
Rate of interest r = 0.08
Compounding frequency n = 2 semi annually
Number of years t = 12
PMT = monthly payment = $?
PMT = [160000 x (0.08/2) x (1+(0.08/2))2 (12) ] / [(1+(0.08/2)2(12)-1]
PMT = [160000 x (0.04) x (1+(0.04))(24) ] / [(1+(0.04)(24)-1]
PMT = [6400 x (1.04))(24) ] / [(1.04)(24)-1]
PMT = [6400 x (2.5633)] / [(2.5633)-1]
PMT = [16405.12] / [(1.5633)]
PMT = 10493.9
So regular semi annual payemt = $10493.9
b) now the total payment during loan period = number of payments x PMT
= 24 x 10493.9 = $251853.6
So total amount paid to house = down payment + total payment during loan
= 150000 + 251853.6 = $401853.6
c) Now the total interest = total loan payment – principal amount
= $251853.6 - $160000 = $91853.6
So total interest = $91853.6
Now we can use the below formula to find the principal amount(P)
PMT = [ P x (r/n) x (1+(r/n)nt ] / [(1+(r/n))nt -1]
P = principal amount = $?
Rate of interest r = 6% = 6/100 = 0.06
Compounding frequency n = 12 monthly
Number of years t = 2
PMT = monthly payment = $300 (maximum)
300 = [P x (0.06/12) x (1+(0.06/12))12 (2) ] / [(1+(0.06/12)12(2)-1]
300 = [P x (0.005) x (1+(0.005))(24) ] / [(1+(0.05)(24)-1]
300 = [P x (0.005) x (1.005))(24) ] / [(1.05)(24)-1]
300 = [P x (0.005) x (1.12715] / [(1.12715)-1]
300 = [P x (0.005635)] / [(0.12715)]
300 = [P x 0.044323]
P = 300 / 0.044323 = 6768.49 ~ 6768.5
So home owner can afford only $6768.5
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