Question

4) Given the kinematic equation below solve for the acceleration à and determine the magnitude of the acceleration after time t - 3 seconds given the displacement vectors below. X=(+10 m )X + ( +7 m) =(+1 m )X+(-3 m) 5) Given the following displacement vectors and their resultant vector, determine the components that are missing. (A, B, and C.) A- ( A ) + (-8 m ) + ( 6 m )2 B = ( 10m 8+ ( B, D + (-3 m)2 + c(-5 mx + ( 4 my +( C )2 R-( 4 m )X + (Om ) + ( 2 m )2 6) Cathy is in a car and the direction of Cathy's velocity is west, there is a net force acting on the car, what is the car doing? (Be careful, Canvas will not have the same order for the answers below!) Must be Speeding up in the west direction Must be slowing down in the east direction Must be Moving at a constant velocity It could be either speeding up or slowing down. It could be either accelerating or moving at a constant velocity. 7) Bob is pulling a wagon by applying a horizontal force, the only other horizonal force acting on the wagon is a frictional force of 20 N acting on the wagon. if Bob want to pull the wagon at a constant velocity, what horizonal force must Bob apply to the wagon? (Be careful, Canvas will not have the same order for the answers below!) Slightly larger than 20 N Significantly larger than 20 N Exactly 20 N Slightly smaller than 20 N Significantly Larger than 20 N Bob does not need to apply a force for the wagon to move at a constant velocity

Answer 1

4 given that, Tg = 5; + tā +² where, ni 11 (tim)ñ +(-3m) & at t=35 5o = (+lom ñ +(472) a so, at t=35 (Glom) ñ +(+72)ů = (tim)ñ +(-3m)ů + Ža, 32

qã= {(10-1) m û +2(7+3) mga 37 ãG-)misy * +4-10-49 a = (+2m/sh) ñ +420 52) + (+2.22222222 mis) a= (+2m152) TI 1 (+2m152) ñ + (+2.2 m/s2) | Cappoon) Ã = (and ñ + (-8m) û + 6m) ê 8 = (10 m) +(B) + (-3m.) e =(-sm)ñt (Am) ↑ + (Cz) (4m) + 9 +(2m) 89 Ant (10m)+(-5m) -4m) Ana (4m)-(lom) + 6 - Anaclm)

Similarly, (-8m) + By + (4m) = 0 By = ( 8-) - (^.^) By = (4m) P finally, (5m) + (-34-) +(?= (2-) - (4-3) + 3) - (6r-) (273-6)m Cz € Cz . (MP) An=tim) By (4m) &z=(-1m)

object, then that nesultunt force For Newton's laws of motion, we know that if there is Net external force on would cause the obtect to change it's velocity & given that Cathy's velocity is towards west. Now if the Net force is directed toward West then cathy's car would speed up toward west, if the net force is towards East, then Cathy would move toward west with decreasing Speed . So the 4th option is connect, i.e, could be either speeding up It or slowing down.

az Ö mis? 3) > f=200 if bob is pulling with a force F & the wagon is moving with constant Velocity ci-e acceleration = 0) then Newton's 2nd law by where, F- of of the wagon of the acceleration, a co is the mass F-f= 0

s ) F = f 2ON so, the 3rd option is correct, i.e exactly con