Question

Problem 9.60 Fuel Gas Combustion A fuel gas containing 55.00 mole% methane and the balance ethane is burned completely with pure oxygen at 25.00°C, and the products are cooled to 25.00°C. Physical Property Tables Continuous Reactor Suppose the reactor is continuous. Take a basis of calculation of 1.000 mol/s of the fuel gas, assume some value for the percent excess oxygen fed to the reactor (the value you choose will not affect the results), and calculate -Q (kw), the rate at which heat must be transferred from the reactor if the water vapor condenses before leaving the reactor and if the water remains as a vapor. State of water -Q (kW) liquid vapor Closed Vessel at Constant Volume Now suppose the combustion takes place in a constant-volume batch reactor. Take a basis of calculation 1.000 mol of the fuel gas charged into the reactor, assume any percent excess oxygen, and calculate - Q(kJ) for the cases of liquid water and water vapor as products. Hint: Eq. 9.1-5. State of water -Q (kJ) liquid vapor

Answer 1

21.65 mol/sec ou required Basis molls of gas CHY = 0.55 H6 =0.45 25°c > Reant Let 50%. excan oxygen CHu 302 202 tho CH. +7010 Bho from stichionesy For 1 molls Cry 3 mol/sec Q required For oss mol/sty 3x0.55 mol/sec O required For 1 mol/sec Catto - 7 nolsee a require For our mosse che – zxous molyse goleir 2.1.575 molleen a o left Total O required 2 1.65+1.5t5 23.225 mol/sec 50% excen a ofed o feda 4.8315 mol/sen 24.8375 -3.225 = 1.6125 mol/sen From Reaction 0 2 = 2X0.55 - 1 loroffsen ho 2x0.55 1.1 mollsen from Reaction ca - 270-452 3.9 molfsee tho. 2x045 20.9 malfsen Tote watha 11 +0.9 2 2moyse.

Heat of formation Chu 2 74.533 kJ mol GHO 2-68.12 ky mol -393.5k] mol hou-285.8 kg/ond for O₂=0 For reaction Dhirx a Evi Producer - {2, Reactions Parc-33}+[4:33 31 -3 -zusche (es) ho Cho 2 - 1284.067 KI mol for 0.55 mole -1284.067x655ky Sk3 / sec 2-766.236 kg for reaction 11 مرے 12(3035) +6221-2301) – (-63:2) - 1290.48 koro) ~1290.48xo.urky for 0.45 mol sa kg/sec = -586.716 kJ/g. Toto Q2 ~706.236+ (-580.716) 2 - 1286-952 - 1286-952 kw (Forvapour) DH = 40.8 kJ/mol {for wat) Q. Bxgfelex 40-8 kg 281.67 19t absorbs heat? not
from heat balance all the values are calculated. In continuous reactor flow is continuous so flow rate is in mole per second. But in constant volume flow will be in mole only. And joule per second is watt.