A volume of 500.0 mL of 0.140 M NaOH is added to 625 mL of 0.200 M weak acid (?a=6.07×10−5).
What is the pH of the resulting buffer?
HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
pH =
We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
A volume of 500.0 mL of 0.110 M NaOH is added to 625 mL of 0.200 M weak acid (K, = 2.11 x 10"). What is the pH of the resulting buffer? HA(aq) + OH(aq) + H2O(l) + (aq)
A volume of 500.0 mL of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid ( ?a=1.66×10−5 ). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.170 M NaOH is added to 545 mL of 0.200 M weak acid (Ka=6.26×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH??
A volume of 500.0 mL of 0.160 M NaOH is added to 605 mL of 0.200 M weak acid.(Ka=8.12×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.160 M NaOH is added to 625 mL of 0.250 M weak acid (Ka = 5.24 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) + H2O(1) + A- (aq) pH =
A volume of 500.0 mL of 0.140 M NaOH is added to 555 mL of 0.250 M weak acid (Ka-5.49 x 10-5). what is the pH of the resulting buffer? HA(aq) +OH(aq)H,0) + A (aq) PH-
A volume of 500.0 mL of 0.140 M NaOH is added to 585 mL of 0.250 M weak acid (K, = 1.73 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) — H, 0(1) + A- (aq) pH =
A volume of 500.0 mL500.0 mL of 0.140 M0.140 M NaOHNaOH is added to 565 mL565 mL of 0.200 M0.200 M weak acid (?a=7.29×10−5).(Ka=7.29×10−5). What is the pHpH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.100 M NaOH is added to 545 mL of 0.200 M weak acid (K, 7.44 x 10). What is the pH of the resulting buffer? HA(aq) + OH (aq) H,O)+A (aq) 4.208 PH
A volume of 500.0 mL of 0.120 M NaOH is added to 525 mL of 0.200 M weak acid (K, = 3.15 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) — H,O(1) + A (aq) pH