A volume of 500.0 mL of 0.160 M NaOH is added to 605 mL of 0.200 M weak acid.(Ka=8.12×10−5). What is the pH of the resulting buffer?
HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid ( ?a=1.66×10−5 ). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (Ka=3.72×10−5). What is the pH of the resulting buffer? HA(aq)+OH-(aq)----->H2O(l)+A-(aq)
A volume of 500.0 mL of 0.170 M NaOH is added to 545 mL of 0.200 M weak acid (Ka=6.26×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH??
A volume of 500.0 mL of 0.160 M NaOH is added to 625 mL of 0.250 M weak acid (Ka = 5.24 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) + H2O(1) + A- (aq) pH =
A volume of 500.0 mL of 0.160 M NaOH is added to 575 mL of 0.200 M weak acid (K, the resulting buffer? 5.93 x 10). What is the pH of HA (aq) +OH (aq)HO) + A (aq) pH = QuestronT orA Calculate the pH of the resulting solution if 35.0 mL of 0.350 M HCl(aq) is added to 45.0 mL of 0.350 M NaOH(aq). pH Calculate the pH of the resulting solution if 35.0 mL of 0.350 M HCI(aq)...
A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (K, = 7.89 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) → H2O(l) + A™(aq) pH II
500.0 mL of 0.160 M NaOH is added to 565 mL of 0.200 M weak acid (K resulting buffer? 3.77x 105). What is the pH of the HA(aq)+OH-(aq) → H2O()-A-(aq) Number
A volume of 500.0 mL of 0.140 M NaOH is added to 625 mL of 0.200 M weak acid (?a=6.07×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH =
A volume of 500.0 mL of 0.110 M NaOH is added to 625 mL of 0.200 M weak acid (K, = 2.11 x 10"). What is the pH of the resulting buffer? HA(aq) + OH(aq) + H2O(l) + (aq)
500.0 mL of 0.120 M NaOH is added to 605 mL of 0.200 M weak acid (Ka = 7.26 × 10-5). What is the pH of the resulting buffer?