A volume of 500.0 mL of 0.170 M NaOH is added to 545 mL of 0.200...

Question

Question

A volume of 500.0 mL of 0.170 M NaOH is added to 545 mL of 0.200 M weak acid (Ka=6.26×10−5). What is the pH of the resulting buffer?

HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)

pH??

Answer 1

Answer #1

pt = pka sooml x 0,170 pH = -log 6:26x10.5): 4.20 HAL + Of Car A (af)+ H₂old) jx 0.170 molos ott 1103 mi solution = 0.0350k m

Answer 2

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