A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (Ka=3.72×10−5). What is the pH of the resulting buffer?
HA(aq)+OH-(aq)----->H2O(l)+A-(aq)
A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (K, = 7.89 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) → H2O(l) + A™(aq) pH II
A volume of 500.0 mL of 0.160 M NaOH is added to 605 mL of 0.200 M weak acid.(Ka=8.12×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.180 M NaOH is added to 565 mL of 0.250 M weak acid (Ka= 4.73 x 10-5) What is the pH of the resulting buffer? HA(aq) + OH-(aq) -> H2O(l) + A-(aq)
A volume of 500.0 mL of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid ( ?a=1.66×10−5 ). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.160 M NaOH is added to 625 mL of 0.250 M weak acid (Ka = 5.24 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) + H2O(1) + A- (aq) pH =
A volume of 500.0 mL of 0.150 M NaOH is added to 525 mL of 0.250 M weak acid (?a=4.43×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH=
A volume of 500.0 mL of 0.140 M NaOH is added to 555 mL of 0.250 M weak acid (Ka-5.49 x 10-5). what is the pH of the resulting buffer? HA(aq) +OH(aq)H,0) + A (aq) PH-
500.0 mL of 0.110 M NaOH is added to 585 mL of 0.250 M weak acid (Ka = 2.27 x 10-5 M). What is the pH of the resulting buffer? HA(aq) + OH(aq) - H2O(l) + A-(aq) pH =
500.0 mL of 0.120 M NaOH is added to 605 mL of 0.200 M weak acid (Ka = 7.26 × 10-5). What is the pH of the resulting buffer?
A volume of 500.0 mL of 0.170 M NaOH is added to 545 mL of 0.200 M weak acid (Ka=6.26×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH??