500.0 mL of 0.120 M NaOH is added to 605 mL of 0.200 M weak acid (Ka = 7.26 × 10-5). What is the pH of the resulting buffer?
A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (Ka=3.72×10−5). What is the pH of the resulting buffer? HA(aq)+OH-(aq)----->H2O(l)+A-(aq)
A volume of 500.0 mL of 0.160 M NaOH is added to 605 mL of 0.200 M weak acid.(Ka=8.12×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (K, = 7.89 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) → H2O(l) + A™(aq) pH II
A volume of 500.0 mL of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid ( ?a=1.66×10−5 ). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
500.0 mL of 0.130 M NaOH is added to 555 mL of 0.200 M weak acid (Ka = 7.11 × 10-5). What is the pH of the resulting buffer?
500.0 mL of 0.150 M NaOH is added to 555 mL of 0.200 M weak acid (Ka = 6.24 × 10-5). What is the pH of the resulting buffer?
A volume of 500.0 mL of 0.120 M NaOH is added to 525 mL of 0.200 M weak acid (K, = 3.15 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) — H,O(1) + A (aq) pH
A volume of 500.0 mL of 0.170 M NaOH is added to 545 mL of 0.200 M weak acid (Ka=6.26×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH??
500.0 mL of 0.160 M NaOH is added to 565 mL of 0.200 M weak acid (K resulting buffer? 3.77x 105). What is the pH of the HA(aq)+OH-(aq) → H2O()-A-(aq) Number
500.0 mL of 0.170 M NaOH is added to 615 mL of 0.250 M weak acid (Ka = 1.08 × 10-5). What is the pH of the resulting buffer?