A volume of 500.0 mL of 0.120 M NaOH is added to 605 mL of 0.250 M weak acid (Ka=3.72×10−5). What is the pH of the resulting buffer? HA(aq)+OH-(aq)----->H2O(l)+A-(aq)
A volume of 500.0 mL of 0.130 M NaOH is added to 605 mL of 0.200 M weak acid ( ?a=1.66×10−5 ). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.160 M NaOH is added to 605 mL of 0.200 M weak acid.(Ka=8.12×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq)
A volume of 500.0 mL of 0.180 M NaOH is added to 565 mL of 0.250 M weak acid (Ka= 4.73 x 10-5) What is the pH of the resulting buffer? HA(aq) + OH-(aq) -> H2O(l) + A-(aq)
A volume of 500.0 mL of 0.150 M NaOH is added to 525 mL of 0.250 M weak acid (?a=4.43×10−5). What is the pH of the resulting buffer? HA(aq)+OH−(aq)⟶H2O(l)+A−(aq) pH=
A volume of 500.0 mL of 0.120 M NaOH is added to 525 mL of 0.200 M weak acid (K, = 3.15 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) — H,O(1) + A (aq) pH
A volume of 500.0 mL of 0.160 M NaOH is added to 625 mL of 0.250 M weak acid (Ka = 5.24 x 10-5). What is the pH of the resulting buffer? HA(aq) + OH(aq) + H2O(1) + A- (aq) pH =
A volume of 500.0 mL of 0.150 M NaOH is added to 615 mL of 0.250 M weak acid (Kg = 4.65 x 10-'). What is the pH of the resulting buffer? HA(aq) + OH(aq) — H,O(l) + A (aq) pH If a buffer solution is 0.230 M in a weak acid (K, = 9.0 x 10-) and 0.460 M in its conjugate base, what is the pH? pH =
A volume of 500.0 mL of 0.140 M NaOH is added to 585 mL of 0.250 M weak acid (K, = 1.73 x 10-). What is the pH of the resulting buffer? HA(aq) + OH(aq) — H, 0(1) + A- (aq) pH =
A volume of 500.0 mL of 0.140 M NaOH is added to 555 mL of 0.250 M weak acid (Ka-5.49 x 10-5). what is the pH of the resulting buffer? HA(aq) +OH(aq)H,0) + A (aq) PH-