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-/25 !!! Current Attempt in Progress Air at atmospheric pressure and a temperature of 25°C is in parallel flow at a velocity
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0, 0281 W/mk Thermophysical properties of air at T= 3256 2 = 18.405 x 10-6ml ka Pr = 0.703 with uniform a) for turbulent flow(0.703) → o.dx hx ha (0.5) -0.008 (5M1SXO.S 0.0281 18.405x10-6 hx=19.664 W/m2K Now: as = hx (Ts (X) - Too] 1250W/ me = 19.664

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