We need at least 10 more requests to produce the answer.
0 / 10 have requested this problem solution
The more requests, the faster the answer.
The % difference = Standard E° (using table) = (show calculation) Ee=Fe+2/ Fe= -0.44V Eo=Cu2+/ Cu=...
please show work and how they got the answer 13. If [Cu2+] = 0.30 M for the same cell described below, then what concentration of Fe2+ is needed to result in Ecell = 0.76 V? You will need to use the standard reduction potential table. Cu2+/ Cu → E = +0.34 V Fe2+/ Fe → E = -0.45 Cu?* (aq) + Fe(s) - Fe* (aq) + Cu(s) Eºcell = +0.78 V, Q = x/ 0.30, X = [Fe2+], Using Nernst,...
39. Given: E +0.46 V Eo- +0.34 V Cu(s) + 2 Ag+ → 2 Ag (s) + Cu2. Cu2+ + H2 (g) → Cu (s) + 2 H' Find the standard potential for the cell reaction for 2 Ag + H2 (g)-2 Ag+2H +0.80 V b. a. +0.40 V +0.12 V d. c. -0.12 v none of these e. 40. Given: Fe (s) + 2 Ag' (aq) Fe (ag)+ 2 Ag (s) with E ell -1.24 V What is the...
ño S5E CH 19 Lab report Template - Compatibility Mode Home Insert Draw Design Layout References Mailings Review View Share o Comments Times New... 11 ν Α Α' Aa À AaBbCcDdEe AaBbCcDc АаВЬСcDdЕ AaBbDdEe AaBbDdEe Paste B I U v ab x x ALA Body Text Heading 1 Heading 2 List Paragraph No Spacing Dictate Styles Pane Sensitivity 2. Fe Fe2+(0.10 M Cu2+(0.10 M)Cu Reaction at anode: Reaction at cathode: Overall reaction: The difference = Standard Eº (using table) =...
question iii 10. An electrochemical cell consists of a standard Fe/Fe electrode (Fe (aq) (1.OM) IFe (aq) (1.0M) IPt(s) and a copper metal electrode ( concentrations) Cu2 (aq) +2e Cu(s) Fe (aq) le Fe (aq) +0.34 V -034 +0.77V Mark what is the corect balanced equation for the spontaneous reac u (aq) Fe (aq) Cu(s)+Fe2 (aq) C) Cu(s) + Fe (aq) Cu (aq) + Fe (aq) α Cu2+(aq) + 2e → Cu(s) + Fe2+(aq) Cu → Cu2ト+20 94 i) (...
1. Voltage reading for Fe-Cu cell 0.60 V 2. Voltage reading for Fe-Zn cell 0.25 V 3. Voltage reading for Cu-Zn cell 0.80 V 4. Fe2+ reduction half-reaction and Esedº Ered 5. Cu2+ reduction half-reaction and Ered Ered 6. Zn2+ reduction half-reaction and Ered Ered 7. Redox reaction of Fe-Cu cell 8. Fe-Cu Ecelº Ecell = 9. Redox reaction of Fe-Zn cell 10. Fe-Zn Ecetº Ece 11. Redox reaction of Cu-Zn cell 12. Cu-Zn Eceitº Ecelº = Questions to consider...
Data Sheet with Sample Data 1. Voltage reading for Fe-Cu cell 0.60 V 2. Voltage reading for Fe-Zn cell 0.25 V 3. Voltage reading for Cu-Zn cell 0.80 V 4. Fe2+ reduction half-reaction and Eredº Ered = 5. Cu2+ reduction half-reaction and Ered Eredº 6. Zn2+ reduction half-reaction and Ered Ered- 7. Redox reaction of Fe-Cu cell 8. Fe-Cu Ecelº Ecetº = 9. Redox reaction of Fe-Zn cell 10. Fe-Zn Ecello Ecelº = 11. Redox reaction of Cu-Zn cell 12....
I need help with questione 1-12 and discussion question 1 and 2. The previous pictures help determine the chart. Please Show Work thank you so much An oxidation half-reaction is characterized by electrons appearing on the product side. The oxidation of aluminum for instance would be represented thusly: Al(s) → Al3+ + 3e- (1) An reduction half-reaction is characterized by electrons appearing on the reactant side. The reduction of ferrous iron for instance would be represented thusly: Fe2+ + 2e...
Table provided below for context Please answer all parts that you can. 1. Which electrochemical cell had the greatest voltage? Identify the anode and the cathode for this pair, the measured cell potential, and the calculated Eºcell- 2. Which electrochemical cell had the smallest voltage? Identify the anode and the cathode for this pair, the measured cell potential, and the calculated Eºcell- 3. If the oxidation and reduction half-reactions are separated in a battery, this means the oxidizing agent is...
Question 7 Using the table of standard reduction potentials shown below, calculate the standard cell potential for a battery based on the following reactions. • Pet2 + 2e + Fe . 2 Li + 2 Li + 2e Reduction Half-Reaction F2 +2e + 2F MnO + 8H+ Se + Mn+2+ 4 H 0 Cl2 + 2e + 20 02 + 4H' + 4e + 2 H2O Ag+ e -- Ag Fet) + e + Fe2 O2 + 2 H2O +...
Using the information in the table: Which combination of metals, if used to create an electrochemical cell, would produce the largest voltage? Liu lur the reaction between Zn and Cu2+ ions is 1.1030 V, we can use the known value for the half-cell potential for zinc to determine the half-cell potential for copper: Zn(s) → Zn2+(aq) + 2e + Cu2+(aq) + 2e → Cu(s) Zn(s) + Cu2+ (aq) → Zn2+ (aq) + Cu(s) E half-cell = 0.7628 V Eºhalf-cell =...