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Two children seat themselves on a sesaw. The one on the left has a weight of 300 N while the one on the right weighs 200 N. T
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Answer #1

Torque on right = (force)*(lever arm) = (200)*(1.5) = -300 Nm....

Also, sum of torque about fulcrum = 0

=> Right torque + left torque = 0

=> (-300) + left torque = 0

=> left torque = (+300 Nm)

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