Question

Two children are sitting on opposite ends of a scesaw of negligible mass. If 40 kg child is 2.0 m from the pivoted point, how
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Answer #1

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Balancing the moments will give the required distance,

Mass (m1) x distance (d1) = mass (m2) x distance (d2l

40 kg x 2 m = 30 kg x Y

Distance, Y = 2.67 m

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