The two children are balanced on a seesaw of negligible mass (this assumption is made to keep the example simple). The first child is 26.0 kg and sits .160 m to the left of the pivot. The seesaw has a mass of 12 kg.
If the second child is 32.0 kg, how far is she from the pivot?
What is the supporting force exerted by the pivot?
The two children are balanced on a seesaw of negligible mass (this assumption is made to...
child a o child a Two children are balanced on a seesaw of mass 11.0 kg. The first child has a mass of 26.0 kg and sits 1.60 m away from the pivot. The center of mass of the seesaw is 0.113 m from the pivot. (a) How far from the pivot does the second child sit if he has a mass of 31.0 kg? (b) What is the supporting force exerted by the pivot? LPivot center of mass
Two children are balanced on a seesaw of negligible mass. The first child has a mass of 26 kg and sits 5m from the pivot. If the second child has a mass of 30kg, how far is she from the pivot?
Question 2 (2 Points) Static Equilibrium - Modified Seesaw (including mass of the seesaw) The two children shown in the Figure are balanced on a seesaw. The first child has a mass of m1= 16.2 kg and sits r1 = 2.1 m from the pivot. The center of mass of the seesaw is r3 = 0.36 m to the left of the pivot (on the side of the lighter child) and assume a mass of M = 13.4 kg for...
3. Two children are playing on a seesaw of negligible mass. The first child has a mass of 20.0 kg and sits 1.2 m from the pivot. (i) If the second child has a mass of 30.0 kg, how far is she from the pivot? (ii) What is the supporting force exerted by the pivot? 4. (a) Three point masses are attached to a massless rigid rod. Mass mi- 1.0 kg is located at x 1.0 cm, mass m 2.0...
A 32.0-kilogram child sits on a uniform seesaw of negligible mass; she is 2.10 m from the pivot point (or fulcrum). How far from the pivot point on the other side will her 22.0-kilogram playmate have to sit for the seesaw to be in equilibrium?
Two children are sitting on opposite ends of a scesaw of negligible mass. If 40 kg child is 2.0 m from the pivoted point, how far from the pivot point will the other 30 kg child sit on the seesaw to be at equilibrium? (draw diagram to show vectors) A uniform 2000 kg beam 10 m long supports a 500 kg weight 3 meters from the right support. Calculate the forces on each of the vertical support columns? (draw diagram...
Two children of mass 18 kg and 29 kg sit balanced on a seesaw with the pivot point located at the center of the seesaw. If the children are separated by a distance of 5 m, at what distance from the pivot point is the small child sitting in order to maintain the balance?
Suppose two children are using a uniform seesaw that is 3.00 m long and has its center of mass over the pivot. The first child has a mass of 30.0 kg and sits 1.40 m from the pivot. (a) Calculate where the second 18.0 kg child must sit to balance the seesaw. (b) What is unreasonable about the result? (c) Which premise is unreasonable, or which premises are inconsistent? Please show work and explanations.
dont know what im doing wrong Suppose a 28.4-kg child sits 0.67 m to the left of center on the same seesaw as the problem you just solved in the PRACTICE IT section. A second child sits at the end on the opposite side, and the system is balanced. (a) Find the mass of the second child. 8.55 kg (b) Find the normal force acting at the pivot point. 362 Your answers to part (a) and (b) are not consistent....
dltión of equilibrium equith from t fros 4.0 kg serves a seesaw for two children. A child of mass 38 kg sits shdition for tTh saw is balanced (in equilibrium). A) Write the rotational child on the lefts acting on the seesaw (with torques included), b) calculate on the right m ren end 1.5 frof mass 0ke uibi he pim from the pivot point. The other child sits on the left end of the seesaw condition for the torques acting...