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I need part b please

40 M 45 MP 50 MPA - For the given state of stress, Part A: determine analytically (using stress transformation equations): 1)

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40 mpa 0 Given that Eny = u5 mpa Scale : Go mpa → ox= -60 mpa tot = -6cm May by=-40 mpazog=-4cm = u5 MPa =4.5cm Kay Scale lcmNow from A&B draw a perpendicolars of length AP=BQ = Eny = 4.5cm. Connect the points P & Q. The line PQ in intersect the o-a2 O2 = 180+20, 20,3 180+ 102 das ini 2) manimum si in-plane shear stress. Eman = CF = 5.7 cm = 57 mpa 2 Orientation id=194° $

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