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1.6 Question 42 The mean of a normal distribution is 60 with a standard deviation of 5. What is the probability of selecting
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Answer #1

42)

The mean of the normal distribution is 60 with a standard deviation of 5.

The probability of selecting a score between raw score of 55 and 68,

\small P(55 \leq X \leq 68)

\small =P(\frac{55-60}{5} \leq \frac{X-\mu}{S} \leq \frac{68-60}{5})

\small =P(-1\leq Z\leq 1.6)

= 0.7865

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