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Question 32 In a normal distribution with a mean of 90.00 and a standard deviation of 10, what percentage of the cases lies b
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Giveo, that, *~ N(90,10). We find, need to pl < 90 < X 8 0 90) - Р Plus 90-90 lo 80-90 <2< 1o EP(-1<z«o) 0.3413 that of cases

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