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The distribution of the height of a male gibbon is normal with a mean of 80...
A large study of the heights of 1170 adult men found that the mean height was...
A large study of the heights of 1170 adult men found that the mean height was 71 inches tall. The standard deviation was 8 inches. If the distribution of data was normal, what is the probability that a randomly selected male from the study was between 63 and 87 inches tall? Use the 68-95-99.7 rule (sometimes called the Empirical rule or the Standard Deviation rule). For example, enter 0.68, NOT 68 or 68%. Round your answer to three decimal places....
Assume that a normal distribution of data has a mean of 12 and a standard deviation...
Assume that a normal distribution of data has a mean of 12 and a standard deviation of 3. Use the 68-95-99.7 rule to find the percentage of values that lie below 9.
The height of an adult male has a mean of 70 inches and a standard deviation...
The height of an adult male has a mean of 70 inches and a standard deviation of 3 inches. Using the SD Rule approximately what percentage of men have heights between 64 and 76 inches? Give a percent, not a decimal QUESTION 3 The number of Matthew McConaughey movies that a typical person has seen has a mean of 4 movies and a standard deviation of 1 movie. The SD rules suggests that 99.7% of people have seen between and...
Assume that a normal distribution of data has a mean of 20 and a standard deviation...
Assume that a normal distribution of data has a mean of 20 and a standard deviation of 5. Use 68 - 95 - 99.7 rule to find the percentage of values that lie above 15. What is the percentage of values lie above 15?
The height of a male college freshman has a normal distribution with mean 71 inches and...
The height of a male college freshman has a normal distribution with mean 71 inches and standard deviation 3 inches. What is the probability of selecting a student whose height is between 72 and 75 inches?
Question 32 In a normal distribution with a mean of 90.00 and a standard deviation of...
Question 32 In a normal distribution with a mean of 90.00 and a standard deviation of 10, what percentage of the cases lies between scores of 80 and 907 50% 68% 34% 100%
Example: The time to complete a standardized exam is approximately normal with a mean of 70...
Example: The time to complete a standardized exam is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes. Using the 68-95-99.7 rule, a) what percentage of students will complete the exam in under an hour? b) what percentage of students will complete the exam between 60 minutes and 70 minutes? 17 of 27 c) in what time interval would you expect the central 95% of students to be found?
To estimate the mean height μμ of male students on your campus, you will measure an...
To estimate the mean height μμ of male students on your campus, you will measure an SRS of students. You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. You want your sample mean x⎯⎯⎯x¯ to estimate μμ with an error of no more than one-half inch in either direction. (a) What standard deviation must x⎯⎯⎯x¯ have so that 95% of all samples give an x⎯⎯⎯x¯ within one-half inch of μμ?...
The Army reports that the distribution of head circumference among male soldiers is approximately normal with...
The Army reports that the distribution of head circumference
among male soldiers is approximately normal with mean 22 and
standard deviation 0.9. Use the Empirical Rule to answer the
following questions.
The Army reports that the distribution of head circumference among male soldiers is approximately normal with mean 22 and standard deviation 0.9. Use the Empirical Rule to answer the following questions What percent of soldiers have head circumferences greater than 22.9? What percent of soldiers have head circumferences between...
-99.7% -95% 68% The figure illustrates a normal distribution for the prices paid for a particular...
-99.7% -95% 68% The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $13,000 and the standard deviation is $500. Use the 68-95-99.7 Rule to find the percentage of buyers who paid between $11,500 and $13,000. Number of Car Buyers 11.300 12.000 12.500 13.000 0.00 14.000 Price of a Model of a New Car 14.500 What percentage of buyers paid between $11,500 and $13,000?
The height of an adult male has a mean of 70 inches and a standard deviation of 3 inches. Using the SD Rule approximately what percentage of men have heights between 64 and 76 inches? Give a percent, not a decimal QUESTION 3 The number of Matthew McConaughey movies that a typical person has seen has a mean of 4 movies and a standard deviation of 1 movie. The SD rules suggests that 99.7% of people have seen between and...
Question 32 In a normal distribution with a mean of 90.00 and a standard deviation of 10, what percentage of the cases lies between scores of 80 and 907 50% 68% 34% 100%
Example: The time to complete a standardized exam is approximately normal with a mean of 70 minutes and a standard deviation of 10 minutes. Using the 68-95-99.7 rule, a) what percentage of students will complete the exam in under an hour? b) what percentage of students will complete the exam between 60 minutes and 70 minutes? 17 of 27 c) in what time interval would you expect the central 95% of students to be found?
The Army reports that the distribution of head circumference
among male soldiers is approximately normal with mean 22 and
standard deviation 0.9. Use the Empirical Rule to answer the
following questions.
The Army reports that the distribution of head circumference among male soldiers is approximately normal with mean 22 and standard deviation 0.9. Use the Empirical Rule to answer the following questions What percent of soldiers have head circumferences greater than 22.9? What percent of soldiers have head circumferences between...
-99.7% -95% 68% The figure illustrates a normal distribution for the prices paid for a particular model of a new car. The mean is $13,000 and the standard deviation is $500. Use the 68-95-99.7 Rule to find the percentage of buyers who paid between $11,500 and $13,000. Number of Car Buyers 11.300 12.000 12.500 13.000 0.00 14.000 Price of a Model of a New Car 14.500 What percentage of buyers paid between $11,500 and $13,000?
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