-99.7% -95% 68% The figure illustrates a normal distribution for the prices paid for a particular...
-99.7% -95% Not everyone pays the same price for the same model of a car. The figure illustrates a normal distribution for the fc prices paid for a particular model of a new car. The mean is $18,000 and the O standard deviation is $2000. Use the 68-95-99.7 Rule to find what percentage of buyers paid between $14,000 and $22,000. 12 14 1618 20 2224 Price of a Model of a New Car (Thousands) The percentage of buyers who paid...
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1800 and the standard deviation is $150. 1350 7500 2100 2250 1650 1800 1950 Distribution of Prices What is the approximate percentage of buyers who paid less than $1500? What is the approximate percentage of buyers who paid less than $1350? What is the approximate percentage of buyers who paid between $1650 and $1800? What is the approximate...
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1400 and the standard deviation is $105. + 1085 1190 1295 1400 1505 1610 1715 Distribution of Prices What is the approximate percentage of buyers who paid less than $1190? % What is the approximate percentage of buyers who paid between $1085 and $1400? at% What is the approximate percentage of buyers who paid between $1190 and $1400?...
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1200 and the standard deviation is $135. What is the approximate percentage of buyers who paid between $1200 and $1605? % What is the approximate percentage of buyers who paid more than $1470? % What is the approximate percentage of buyers who paid less than $795? % What is the approximate percentage of buyers who paid between $1200...
The graph illustrates a normal distribution for the prices paid for a particular model of HD television. The mean price paid is $1400 and the standard deviation is $105. 1085 1295 1610 1715 1190 1400 1505 Distribution of Prices What is the approximate percentage of buyers who paid less than $1190? 2.5 % What is the approximate percentage of buyers who paid between $1085 and $1400? 4% What is the approximate percentage of buyers who paid between $1190 and $1400?...
Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 29 and a standard deviation of 4. What percentage of the values in the distribution do we expect to fall between 29 and 377 25% 5% 47.5% 95%
Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 21 and a standard deviation of 4. What percentage of the values in the distribution do we ex between 17 and 217 25% 34% 68% ОО 17% Question 35 of 40
Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 29 and a standard deviation of 4. What percentage of the values in the distribution do we expect to fall between 29 and 37? 95% 5% 25% 47.5% Click comnloto this accorcmont
2.5 points Use the 68-95-99.7 rule to solve the problem. Assume that a distribution has a mean of 21 and a standard deviation of 4. What percentage of the values in the distribution do we expect to fall between 17 and 212 68% 25% 17% 34%
Use the 68-95-99.7 rule to approximate what proportion of observations in N(70,5) distribution fall between 70 and 80. (Show your answer in percentage.)