3.
If a proton is moving along the x-axis at 8/10 times the speed of
light in vacuum, through a region of space where the Electric field
is 2i and the Magnetic field 3i+4j, find the magnitude of the force
on the proton.
Since proton is moving with such high velocity. Hence on solving for magnitude of force we have to neglect smaller value i.e due to electric field.
3. If a proton is moving along the x-axis at 8/10 times the speed of light...
Score: E-peild Imagine a proton moving initially at 2.1x 10 m/s in the positive direction of the x-axis. It moves in a field-free space until it passes by the origin, x-0, where it encounters an electric field directed along the x-axis. (The y and z components of the field are zero everywhere.) The electric potential, vto), associated with this field is shown i the left graph for 0x70 cm. 250 200 E 150 100 8 50 0 10 20 30...
In a vacuum, a proton (charge = +e, mass = 1.67 times 10^-27 kg) is moving parallel to a uniform electric field that is directed along the +x axis (see figure below). The proton starts with a velocity of +4.30 times 10^4 m/s and accelerates in the same direction as the electric field, which has a value of +5.70 times 10^3 N/C. Find the velocity of the proton when its displacement is +2.0 mm from the starting point. Number Units...
1. An electron moving along the +X-axis with a speed of 3x105 m/s when it enters a region of uniform magnetic field with strength of 10 T in the +y- direction. What is the Electric field in the region if the electron maintains its initial velocity? Give your answer in component form.
Imagine a proton moving at 2.1 x 10m/s in the positive direction of the x-axis. It moves in a field-free space until it passes by the origin, x = 0, where it encounters an electric field directed along the x-axis. (The y and z components of the field are zero everywhere). The electric potential, V(x), associated with this field is shown in the graph below. 200 Hlectrical (V) 100 50 0 0 10 20 30 40 50 60 70 Position...
A proton moving along the +x-axis enters a magnetic field. Because of this field the proton curves downward (in the -z direction). What is the direction of the magnetic field.
. An electron is moving (along x-axis) through a 50 T magnetic field (along y-axis) at a perpendicular velocity of 20000 m/s. Find the magnitude and direction of the magnetic force experienced by the electron. having hard time pleases go step by step
An electron is moving (along x-axis) through a 77 T magnetic field (along y-axis) at a perpendicular velocity of 20000 m/s. Find the magnitude and direction of the magnetic force experienced by the electron. (Here is a picture not sure if you need it. if not disregard.) I P В.
An electron is moving (along x-axis) through a 50 T magnetic field (along y-axis) at a perpendicular velocity of 20000 m/s. Find the magnitude and direction of the magnetic force experienced by the electron. which law is this using and can you break it down step by step im still not understanding
A proton moves through a magnetic field at 28.7% of the speed of light. At a location where the field has a magnitude of 0.00679 T and the proton\'s velocity makes an angle of 115° with the field, what is the magnitude of the magnetic force acting on the proton? ___ N
A proton moves through a magnetic field at 29.7% of the speed of light. At a location where the field has a magnitude of 0.00697 T and the proton's velocity makes an angle of 123° with the field, what is the magnitude of the magnetic force acting on the proton?