A proton moves through a magnetic field at 28.7% of the speed of light. At a...
A proton moves through a magnetic field at 28.7% of the speed of light. At a location where the field has a magnitude of 0.00679 T and the proton\'s velocity makes an angle of 115° with the field, what is the magnitude of the magnetic force acting on the proton?
___ N
Homework Answers
Here F=q*v x B
where q=1.6 x 10^-19 C
v=0.287*(3 x 10^8 m/s)= 8.61 x 10^7 m/s
B= 0.00653T*Sin115°
Solving for F
F= (1.6 x 10^-19 C)*(8.61 x 10^7 m/s)*(0.00679T*Sin115°)
F= 8.48 x 10^-14 N Answer
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