Question

The amount of time adults spend watching television is closely monitored by firms because this helps to determine advertising pricing for commercials. Complete parts (a) through (d). (a) Do you think the variable "weekly time spent watching television" would be normally distributed? If not, what shape would you expect the variable to have? A. The variable "weekly time spent watching television" is likely uniform, not normally distributed. B. The variable "weekly time spent watching television" is likely skewed right, not normally distributed. C. The variable "weekly time spent watching television" is likely skewed left, not normally distributed. D. The variable "weekly time spent watching television" is likely normally distributed. E. The variable "weekly time spent watching television" is likely symmetric, but not normally distributed. (b) According to a certain survey, adults spend 2.45 hours per day watching television on a weekday. Assume that the standard deviation for "time spent watching television on a weekday" is 1.93 hours. If a random sample of 60 adults is obtained, describe the sampling distribution of x, the mean amount of time spent watching television on a weekday. with Hy x is approximately normal ; = 2.45 and 0- = 0.249162'. (Round to six decimal places as needed.) X (c) Determine the probability that a random sample of 60 adults results in a mean time watching television on a weekday of between 2 and 3 hours. The probability is (Round to four decimal places as needed.)

Answer 1

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Sol:- given ll= 2-45 1.93 6 = n= 60 Mean of sampling distribution ll. el=(2.45 stod der 5.- 1-93 V Go Oo 249162 un Requiered probability PC&<x<3) مر - 3-2.45 < < 2-2.45 0-249162 slun 0-249162 = P(-1-81< Z<2.21) = P(Z < 2.21) - P(Z2-1-81) 0.9864474 - 0.0351479 0.9513 l]