a)
option C) is correct
skewed right,
b)
Xbar is approximately normal
mean = 2.25
sd(Xbar )= sd/sqrt(n) = 1.93/sqrt(40) = 0.30516
c)
P( 2 < xbar < 3)
=0.7867
d)
P(Xbar < 1.79)
= P(Z <(1.79 - 2.25)/((1.93/sqrt(35))
= P(Z < -1.41005 )
= 0.07930
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