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The R = 650-W resistor, C = 4.0-mF capacitor, and L = 0.16-H inductor are connected...

  1. The R = 650-W resistor, C = 4.0-mF capacitor, and L = 0.16-H inductor are connected in series to an AC (sinusoidal) source. What should be the maximum source voltage V0 to have the maximum current I0 = 0.15 A if the source frequency f=60 Hz?

Which of the following statements is/are correct. If the source frequency increases:

  1. Inductive reactance decreases;
  2. Capacitive reactance increases;
  3. Inductive reactance increases;
  4. Capacitive reactance decreases;
  5. A and B;
  6. C and D.
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Answer #2

(2.7 0:16) u 그 xe 2afe R = 6500, < =4.0.4F, 170.16 ,f=6042 Now indutive Veartance L-2152 (2.1X 60 8.16) 60.3 Capacitive indulIndutive Yeartance Capacitive realfance XL = 275L it at fa now If increase then * will increase but Xe will decrease. option

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Answer #3

R = 6502, (= 4X10-3f, x10-3F, L-0:16h f=6012 X = 20fl = 60.32 1 Xc= 0.663 R zafe 6532 2= R²+(x2 - (+)) ² Vo = 12- (0.1) (637)

Kindly upvote:)

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Answer #6

5.

In RLC circuit,

Impedance is given by:

Z = sqrt (R^2 + (XL - Xc)^2)

R = 650 ohm

XL = w*L = 2*pi*f*L = 2*pi*60*0.16 = 60.31858 ohm

Xc = 1/(2*pi*f*C) = 1/(2*pi*60*4.0*10^-6) = 663.14560 ohm

Z = sqrt (650^2 + (60.31858 - 663.14560)^2) = 886.51 ohm

Now using ohm's law:

Vmax = Imax*Z

V0 = I0*Z

V0 = 0.15*886.51 = 132.9765 V

V0 = max source voltage = 133 V

5B.

XL = 2*pi*f*L

So Inductive reactance is directly proportional to the source frequency, which means if frequency is increased then Inductive reactance will also increase.

Xc = 1/(2*pi*f*C)

So Capacitive reactance is inversely proportional to the source frequency, which means if frequency is increased then Capacitive reactance will decrease.

Correct option is F. (C and D)

Let me know if you've any query.

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Answer #5

Maximum valtage V_0= I_0R= 0.15\times 650 = 97.5 Volt.

Inductive reactance X_L= 2\pi fL

And Capacitive reactance X_C= \frac{1}{2\pi fC}

where f , C , L are the frequency, capacitance and inductance.

So, if source frequncy increases, Inductive reactance increases and capacitive reactance decreases.

Ans: F. C and D.

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Answer #4

series LCR circuit, maximum current is obtained when Xl=Xc

so the circuit behaves as purely resistive.

V=IZ

V=IR

V=0.15*650

=97.5 volt

inductive reactance, Xl=2\pi \nu L and capacitive reactance, X_{c}=\frac{1}{2\pi \nu C}

so it is clear when frequency increases Xl increases and Xc decreases.

correct option=F

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Answer #1

- y!! Z Given: R= 650 Impedence of the Cirwit is given by, in C= 4MF=4x1632 L= 0.16H. Z-TR’+ (x2-x2) Io = 0.15A f = 6043 (650

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