Aresearcher selected a random sample of 10 psychology graduates and found the standard deviation of their...
The mean and standard deviation for the quality grade point averages of a random sample of 28 senior high school students are calculated to be 2.6 and 0.3 respectively. What is the point estimate for the mean? What is the point estimate for the variance?
The mean and standard deviation for the quality grade point averages of a random sample of 28 senior high school students are calculated to be 2.6 and 0.3 respectively. what is the point estimate for the mean? what is the point estimate for the variance?
Question 10 (1 point) For a random sample of 15 recent business school graduates beginning their first job, the mean starting salary was found to be $35,500, and the sample standard deviation was $7,500. Assuming the population is normally distributed, calculate the lower confidence limit (LCL) of the population mean with a -0.01. Your Answer:
In a hospital, a random sample of 10 weeks was selected, and it was found that an average of 495 patients were treated in the emergency room each week. The population standard deviation was 23. Find the 90% confidence interval of the true mean. Assume the variable is normally distributed. (Show Work)
A random sample of 50 students is selected and it is found that the mean of daily internet usage is 70.8 minutes with standard deviation of 13.8 minutes. A hypothesis test was performed to determine whether the true mean usage, µ equal to 72.0 minutes or not. What is the p-value of the test?
A sample of 16 items provides a sample standard deviation of 9.5. Test the following hypotheses using a 0.05. What is your conclusion? Ho: o s 50 H,:o? > 50 Use the p-value approach. Find the value of the test statistic. 27.075 Find the p-value. (Round your answer to three decimal places.) p-value = 0.028 State your conclusion O Reject No. We conclude that the population variance is greater than 50 Do not reject No. We conclude that the population...
The owner of a local nightclub has recently surveyed a random sample of n = 250 customers of the club. She would now like to determine whether or not the mean age of her customers is greater than 30. If so, she plans to alter the entertainment to appeal to an older crowd. If not, no entertainment changes will be made. Suppose she found that the sample mean was 30.45 years and the sample standard deviation was 5 years. Assume...
At a college, 61 female students were randomly selected and it was found that their monthly income had a standard deviation of $230.85. For 121 male students, the standard deviation was $320.53. Test the claim that variance of monthly incomes is higher for male students than it is foi female students. Use a = 0.01.
The mean SAT score in mathematics, μ, is 551. The standard deviation of these scores is 33, A special preparation course claims that its graduates will score higher, on average, than the mean score 551. A random sample of 43 students completed the course, and their mean SAT score in mathematics was 556 Assume that the population is normally distributed. At the 0.05 level of significance, can we conclude that the preparation course does what it claims? Assume that the...
The mean SAT score in mathematics, u, is 512. The standard deviation of these scores is 25. A special preparation course claims that its graduates will score higher, on average, than the mean score 512. A random sample of 25 students completed the course, and their mean SAT score in mathematics was 520. Assume that the population is normally distributed. At the 0.1 level of significance, can we conclude that the preparation course does what it claims? Assume that the...