For the planetary gear set, =0 rpm, = arm= 280rpm, and the number of teeth in...

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For the planetary gear set, =0 rpm, = $\omega$ arm= 280rpm, and the number of teeth in the gears are, N2=27, N5=39, N6=73 and N7=70, what is the angular velocity of gear 2, $\omega 2$ in rpm.

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planetary Geor ser- elf=o, elz=ed Arm el 3 =2800pm 3 N2=27 105= 39 7 NG=73 7711 N770 6 Compounded + 7 do Simple Method . Simp Wa Waom Nfx NSX NZ NaX N4X NG Inf -warm 39x70 280 w 2 = 27* 73 -280 xo CA0 -280 2 -1-3850 - 280 387.823 +280 ela 667.823 rpm

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