X-bar of Sample 1 = (495+500+505+500)/4 = 500
X-bar of Sample 2 = (500+490+456+490)/4 = 484
X-bar of Sample 3 = (505+456+485+474)/4 = 480
X-bar of Sample 4 = (500+490+474+504)/4 = 492
Given that,
UCL = 503
LCL = 481
From X-bar values we can see that X-bar value of sample 3 is not in the control limit.
Hence,
We can conclude that Sample 3 is out of control as per given UCL & LCL.
I need help with my test review question please A design engineer wants to construct a...
QUESTION 13 A design engineer wants to construct a sample mean chart for controlling the service life of a halogen headlamp his company produces. He knows from numerous previous samples that this service life is normally distributed with a mean of 500 hours and a standard deviation of 20 hours. On three recent production batches, he tested service life on random samples of four headlamps, with these results: Service life in hours Sample 1 Sample 2 Sample 3 Sample 4...
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