Question

Not yet answered ad out of 3.00 4 5 6 Flag question The motion of a particle is defined by the equations x = (2x + 1)m and y = (t?) m, where t is in seconds. Determine the normal and tangential components of the particle's velocity and acceleration when t = 2s. 10 Select one O a 1721 vs. Vnomis, at 277 m2, an 0.55 m2 Ob V 279 ms, Vn 46 s. at 733 m2, an 0.44 m2 O CV-53 ms. Vn32 ms. at 62 m2 an- 15552 Od V6.0 ms, Vn 4.0 ms. at 20 m/s2 ans 20 m2 O e Vi= 1.55 m/s, Vn=62 ms, at 5.3 m/s2 ane 32 m2

Answer 1

Guiven CH 2t + E2 y = t² Velocity (ve)) dn 3 dy 7 clt at r (27) P 76m), 100 (ut 2t) ( 34 fre), 262) 19 Lt at 1 7 / 125 J t=25 16, 64+42 Magnitude of reberity 3.7:21 Al 7.21 mil

news portato (51) ( ) dy dth dth d (2) dt ålt) v ܢ Magnitude of Acceleration 5 Ax? tay? 2 ܐ ܐ ܕܐܬ{* = 2.82 mi? Note. Companing Magnitude of acceleration for all options Option b, option c and option E are weerg since magnitude of acceleration 2.82

Total Acceleration in option A and option D is Equal to 2.12mi - Total Acceleration of A A. 2.77² +0.552 2.82m 5-2 Toto Acceleration of D = 12h + 22 2-12ms No normal Velocity ein Question Vnzo gevin 1 Thus Option A is Commect Anwen Amu