Question 8 How much ice at 0°C is needed to cool 200 g of water from...

Question

Question

Answer 1

Answer #1

Answer: 43 g.

Solution:

Given,

L_f = 3.33 x 10⁵ J/Kg = 79.58 Cal/g

C_w= 4186 J/kg^oC = 1 Cal/g^oC

Total amount energy required by water at 32^oC to cool down to 12^oC,

H = m.C_w.(T_f-T_i)= 200 x 1 x (32-12) = 4000 calories.

Suppose m ice is needed for this,

So, total heat released by ice = m x 79.58 + m x 1 x 12 = 91.58 m

Equating heat release and required,

91.58m = 4000 cal

m = 4000/91.58 = 43.6 gram

so, m = 43 gram (approx)

Answer 2

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