Question

Questions Water is howing through a circular pipe with a radius of 0.30m at 340m's. If the pipe's radius tapers down to 020m, what is the speed of water through the narrower end! Answer inms 0.50 0600 0200
show work please

Answer 1

Cross sectional area of a circular pipe having radius r meter is,

A = Πr²

Now, according to equation of continuity,

Av = constant.

Hare, v = velocity of the liquid.

Given in the question,

At radius r₁ = 0.30 m , velocity , v₁ = 3.40 m/s

Let, ar radius , r₂ = 0.20 m, velocity is v₂ .

Thus from equation of continuity,

r₁​​​​​​²v₁ = r_2²v₂

Or, 0.30×0.30×3.40 = 0.20×0.20 × v₂

Or, v2 = (0.30×0.30 × 3.40 )/0.20×0.20 = 5.1 m/s

Answer : 7.65 m/s