Of the two compounds which compound
will have higher standard molar entropy at 25
oC:
Answer is II.
Cyclobutane (I) is symmetrical structure as rotation of this molecule give similar structure whereas butene (II) is not symmetrical thus degree of disordered arrangement is more in butene than that in cyclobutane hence butene has high molar entropy.
Of the two compounds which compound will have higher standard molar entropy at 25 oC: H H...
of the two compounds which compound will have higher standard molar entropy at 25°C: CH3 Hac # H (1) (II)
Please explain which. Thanks.
of the two compounds which compound will have higher standard molar entropy at 25 °C h H CH H H <I TIN
Calculate the standard entropy change for the reaction at 25°C. Standard molar entropy values can be found in this table. HCl(g) + NaOH(s) + NaCl(s) + H,O(1) AS mol)
For each pair of substances, choose the one that you expect to have the higher standard molar entropy (s ) at 25 degrees celsius 1) NaNO3(s) or Na NO3 (aq) 2) CH4(g) or CH3CH3(g) 3) Br2(l) or Br2(g) 4) Br2(g) or F2(g) 5) PCl3(g) or PCl5(g) 6) CH3CH2CH2CH3(g) or SO2(g)
For each pair of substances, circle the one with the higher standard molar entropy (S°) at 25 °C. Explain a. I(s) or I(g) Reason:________________________________________________________ b. C(s, diamond) or C(s, graphite) Reason:_______________________________________
Without referring to a data table, arrange the compounds from highest to lowest standard molar entropy, Sº. Highest S Lowest S Answer Bank N,(g) C,H,() H,()
1) Explain the trends of standard molar entropy values for the following compounds: He HBr HC HFie 206.3 198.6 186.8 So (JK1mol) 173.1 b) N2O4le) NO2() NO) 304 So (JK mol1) 240 211
1) Explain the trends of standard molar entropy values for the following compounds: He HBr HC HFie 206.3 198.6 186.8 So (JK1mol) 173.1 b) N2O4le) NO2() NO) 304 So (JK mol1) 240 211
Which of the substances below will have the greatest standard molar entropy? C4H10(g) C4H10(l) Xe(g) Which of the substances below will have the greatest standard molar entropy? C4H10(g) C4H10(l) Xe(g) C4H10(g), because it is a gas and as such has translational, rotational, and vibrational modes, allowing for greater energy dispersal C4H10(l), because it is a liquid, so the molecules are in close contact with one another, making the dispersal of energy more efficient Xe, because it has the greatest molar...
1. Which of the following will have the greatest standard molar entropy (Sº)? a. NH3(g) d. H:0(1) b. He(g) e. CaCO(s) c. C(s, graphite) 2. Indicate which of the following has the highest entropy at 298 K. a. 0.5 g of HCN b. 1 mol of HCN c. 2 kg of HCN d. 2 mol of HCN e. All of the above have the same entropy at 298 K. EVALUATING AS FOR REACTIONS (non-math recognition) 3. Indicate which one of...
Identify the compound with the higher boiling point in each of the following pairs of compounds: 1. CH2-CH2-OH or H--C--0--CHz OH 2. CHz---0-CH3 or CH3-CH-CH2-CH3 0 2, CH, -- pH 3. CHz--2-0-CH, or CH3-CH2-CH2-CH2-CH3 Write the products of hydrolysis or saponification for the following esters. н" 1. CH3-CH-CH2--0--0--CH3 + H2O O 2, CH4-C-0-CH + NaOH 3. O -8-6-CH2-CH; -CH ---CH3 + KOH — -0--CH-CH2-CH3 + H20 - Properties of Esters sters shave higher boiling points than alkanes but lower than...