DISTRIBUTION FACTOR ( DF)
JOINT |
MEMBER |
K |
∑K |
DF = K/∑K |
B |
BA BC |
4EI/L= 4EI/20 3EI/L= 3EI/20 |
4EI/20+3EI/20 = 0.35EI |
0.571 0.428 |
FINAL MOMENTS CALCULATION
JOINT |
A |
B |
C |
|
MEMBER |
AB |
BA |
BC |
CB |
DF |
0.571 |
0.428 |
||
FED |
0 |
0 |
-36.249 |
7.5 |
BALANCING |
0-36.249= -36.249 |
|||
36.249X0.571 =20.698 |
36.249X0.428 =15.514 |
|||
COM |
20.698/2 =10.349 |
|||
TOTAL MOMENT |
0+10.349 =10.349 |
0+20.698 =20.698 |
-36.249+15.514 =-20.735 |
7.5 |
MAB= +10.349 Kip.ft |
MBA= +20.698 Kip.ft |
MBC= -20.735 Kip.ft |
MCB= +7.5 Kip.ft |
C2 Done session.masteringengine AA <HW11 - Attempt 1 Problem 3 < 3 of 4 > For...
C2 Done session.masteringengine AA <HW11 - Attempt 1 Problem 3 < 3 of 4 > For the continuous beam shown in , assume Ais IC -20 ft- -20 ft -15ft - fixed and B and Care rollers. Let w = 0.8 kip/ft, P=0.5 kip, and assume Elis constant. Use this beam to answer Parts A though C below. Part A Complete rows three and four of the moment distribution table below by determining the distribution factors (DF) and fixed-end moments...
Done session.masteringengine AA <HW11 - Attempt 1 Problem 3 < 3 of 4 > For the continuous beam shown in , assume A is w D -20 ft -20 ft -15- fixed and B and Care rollers. Let w = 0.8 kip/ft, P=0.5 kip, and assume Elis constant. Use this beam to answer Parts A though C below. Part A Complete rows three and four of the moment distribution table below by determining the distribution factors (DF) and fixed-end moments...
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