Question

The cross section of the hose is circular. The circumference of a circle is 2πR and the area of a circle is πR², where R is the radius of the circle. 1 milliliter = 1 cm³.

If the inner diameter of the hose is 0.98 cm, and the water flows in the hose with a speed of 0.63 m/s, what is the volumetric current Q of the water flowing in the hose (in milliliters per second)?

Answer 1

Given,

Inner diametero the circular hose, d = 0.98 cm

water flowspeed, v = 0.63 m/s = 63 cm/s

Volumetriccurrent, Q = Av

Q = ($\pi$d²/4)v

Q = $\pi$ vd²/4

Q = ((22/7) x 63 x 0.98²)/4

Q = 47.54 cm³/s

Q = 47.54 ml/s , ( 1 cm³ = 1ml)

Answer : Volumetric current, Q = 47.54 ml/s

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