Question

The next three questions concern water flowing in or from a hose. The cross section of the hose is circular. The circumference of a circle is 2R and the area of a circle is TR2 where R is the radius of the circle. 1 milliliter = 1 cm3.

Answer 1

16 d = 1:24cm , v-0.82 m 2 m/s T d² v M 4 = 1 x (1024)?cm x 0.82 m S 2 cm *0.82 x 100 cm 4 Лх (1.24) 4 98.47 S cm3 S 98.47 mililiter (Answer S 17 2 da 1-2 cm A = 0.16cm² v=4.ur em/s Q = 6 cm² x 4.4 X 100 cm 70.4 cm3 0116cm s = 70.4 mililiter (Arcuer) s

Answer 2

SOLUTION 

16.

Q = A * v = pi/4 (1.24)^2 * 0.82*100. cm^3/s (milliliteres per sec)

=> Q = 99.03 milliliters/sec (ANSWER).

17.

Volumetric current remains unchanged.

So.

Volumetric current after partial blocking or before

= 0.16 * 4.4 * 100  

= 70.4 millilitres/sec (ANSWER)