Question

The cross section of the hose is circular. The circumference of a circle is 2πR and the area of a circle is πR², where R is the radius of the circle. 1 milliliter = 1 cm³.

1.If the inner diameter of the hose is 0.98 cm, and the water flows in the hose with a speed of 0.63 m/s, what is the volumetric current Q of the water flowing in the hose (in milliliters per second)?

2.If the inner diameter of the hose is 1.2 cm, but you partially cover the opening of the hose leaving an open area of 0.39 cm²at the end of the hose so that you can spray your friends. The water flows out at 4.7 m/s. What is the volumetric current in milliliters per second now?

Answer 1

Volume flowrate å = AU A = Area U= velocity Area of hose AF TRI? A,= 3:14 (0.98)? A1 = 3.017cm2 speed U = 0.63 m/s = 63cm/s so volume flow rate (6) ö= 3.017X63 a = 190.08 cm/s 0 = 190.08 millifheksels 12) Asea of sprea Az A - TR2 = 3.14 x 0.392 | A2=0.478 cm² speed= 4.7m/s = 470cm is volumepic Cursent & Q = A2ų = 0.4788470 = 224.58cm3/s Q = 224-58 milliliter see 3