Question

E. Identify the species in the highest oxidation state. : NH NH₂ c =y: HEN А D E

Answer 1

Oxidation number According to charge distribution and on the bases of electronegativity we can calculate oxidation state of each atom in organic molecule by simple manner. RELATIVE OXIDATION NUMBER RELATIVE ELECTRONEGATIVITY -1 C +1 -Н C > N> N IUU -1 N +1 -Н CH 0 0 C +1 H H+1 +1 H +1 +1 HLH ✓ -4 H -1 C -Н nu -1 -1 +1 +1 H +1 +1 overall oxidation state of carbon is 4 and each hydrogen is +1. H +1 -1 H nu +1 H +1H -1 +1 H -1 C N when -1 -3 H +1 H -2 -CH3 +1 -2 H3C H +1 EACH HYDROGEN ON +1 OXIDATION STATE OXIDATION STATE OF NITROGEN IS-3 AND OXIDATION STATE OF CARBON IS-2

Explanation for (A) -2 -2 -2 -2 -3 H*1 H -2 -1 N с -2 +1 -1 -1 0 0 -11.1 +1 H H no -2 H2C -2 -2 -2 CH2 с H- H2 H2C -2 CH2 -2 Oxidation number of each hydrogen = +1 Oxidation number of nitrogen = -3 Oxidation number of carbon atom in which CH2 is directly connected to nitrogen atom = -1 Oxidation state of CARBON in -CH-N = 0 Oxidation state of carbon atom in which both carbon connected as CH2-CH2 = -2 Therefore, highest oxidation number in given compound is = +1 (each hydrogen)

Explanation for (B) - H H 174 +1 -3 +3 -1 C N th H. -3 +1 -3 +3 H3C-CEN Each hydrogen having +1 oxidation state Therefore highest oxidation state of given compound is +3

Explanation for (C) +1 -1 -2 H 1 H N +1 +2 H -1 +1 H C-H +1 o 1-1 +1 H H -1 -1 +1 H +1 +1 -3 H H N +1 II C CH3 -1 -1 Therefore, highest oxidation state is +2

Explanation for (D) +1 H H +?, ' -1 -11 +1 N-H +1H-C -1 +1 -1 +1 H-1 +1 C-H +1 N H-1 -1 H -1 +1 +1 -3 -NH2 5 H2N Therefore, highest oxidation state is +1 for each hydrogen

Explanation for (E) -3 H N -2 -2 Therefore, highest oxidation number is +1 for for each hydrogen Answer :- OPTION (B) IS CORRECT