1) Ba2+
Oxidation state of mono ion = charge on ion = +2
Answer: +2
2)
SO2
Oxidation number of O = -2
lets the oxidation number of S be x
use:
2* oxidation number (O) + 1* oxidation number (S) = net charge
2*(-2)+1* x = 0
-4 + 1 * x = 0
x = 4
So oxidation number of S = +4
Answer: +4
3) SO42-
Oxidation number of O = -2
lets the oxidation number of S be x
use:
4* oxidation number (O) + 1* oxidation number (S) = net charge
4*(-2)+1* x = -2
-8 + 1 * x = -2
x = 6
So oxidation number of S = +6
Answer: +6
4)
This is compound of Zn2+ and SO42-
Oxidation state of mono ion = charge on ion = +2
Answer: +2
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