Question

1. Determine the following for the complex; [Cr(CI),(en),](NO), Coordination number: Oxidation number of the metal: (Show your work) number of d electrons on the metal: 2. An aqueous solution of a metal complex absorbs light at 420 nm. What is the color of the solution? What is the energy of the electron transition? (Show your work)

Answer 1

17 for ez cene] (NO3)2 ve [Cr Chem),]4 2003 U N +2 N 6 - t2 15 22plastspeast 325 te coordmation no of if the oxidation state of lo=n. 2+2X(-1) +2x0 x = +4 & oxidation state of or = +4 Electronic configurator of cr= (total no ofe- =24) more state no of a electron = 5. electronic configuration But according to madelung rule electronie contreferatron 1522822p635²326 45² 3d4 nod a electrom=4. 23 An aqueomasta afmetul complex absorbs ught at a warclength 420 mm. uterature survey complementary colour wavelength (mm) colour <400nm 400-450nm 450-490nm 490 550 nm UV nout Blue Gmien Yellow colourles Yellow Orange ked nout atte Blue Green 550-580 mm 580-650 nm 650-750 nm enten Orange Red wavelength le, the compound ade orbe 420 mm in violet colour. Heny colour of the V 4 Y sclation is yellow colour wheel.

We know E = hef - whine & energy h Planck constant C speed speed of light A Warelingth. Hother E = 6.62681054 387 3x108 Inst 420x10-9m (1 mm = 10 6-626x10 34 x3x108] 420 X10 9 - 4.73x10-19 } CY losslot) dit is hou www.spolobam bio 27 table o to light it on to alegre kote of the word spinerne 0 powroopa