Please show steps. Thank you. Consider the reaction: NH3 (g) + HCl (g) NHỊd(s). Given the...
Consider the reaction: NH3 (g) + HCl (g) → NH4Cl (s) Given the following table of thermodynamic data at 298 K: Substance! AH/M/mol) I s。(J/K-mol) NH3 g) HCI (g) NHCI)-3144 -46.19 -92.30 192.5 186.69 94.6 The value of K for the reaction at 25 °c is
Consider the reaction, NH3 (8) H HC ENH1G(s) Given the following table of thermodynamic data at 298 K: Substana | AH¢{kj/mol | Sº C/K-mol) NH3 (5) 16:19 192.5 HCl (8) 92150 186,69 NHCl (s) 13144 94.6 The value of K for the reaction at 25°C is
26. Consider the reaction: (5 pt) NH; (g)+ HCl(g) → NHACI(S) Given the following table of thermodynamic data, Substance AHF (kJ/mol) S /mol.K) NH3 (8) -46.19 1925 HCI (8) -9230 186.69 NH4Cl (s) -3144 946 a. Determine the temperature (in °C) which the reaction is spontaneous Circle one Greater than Less than All None Temp: * Reaction is (non)spontaneous at all temperatures b. Calculate the K for this reaction at 100°C. Answer:
Consider the reaction HCl(g)NH3(g)>NH4C1(s) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.45 moles of HCl(g) react at standard conditions. ASO surroundings J/K Consider the reaction HCl(g)NH3(g)>NH4C1(s) Using standard thermodynamic data at 298K, calculate the entropy change for the surroundings when 2.45 moles of HCl(g) react at standard conditions. ASO surroundings J/K
Consider the reaction: FeO (s) + Fe (s) + O2(g) → Fe2O3 (s) Given the following table of thermodynamic data at 298 K: Substance ΔHf° (kJ/mol) S° (J/K⋅mol) FeO (s) -271.9 60.75 Fe (s) 0 27.15 O2 (g) 0 205.0 Fe2O3 (s) -822.16 89.96 The value K for the reaction at 25 °C is ________. A.370 B.7.1 x 1085 C.3.8 x 10-14 D.5.9 x 104 E.8.1 x 1019
step by step please TT1 pts Consider the reaction: NHą (g) + HCI (g) → NH,CI (s) Given the following table of thermodynamic data at 298 ok: Substance (kJ/mol S(J/mol) NH |-46.19 192.5 HCI -92.30 186.69 NHCI -314.4 94.6 The value of K for the reaction at 25 °C is 150 1.4 x108 1.1 x10-16 9.3 Ⓡ1015 8.4 x104
Calculate the ΔH0 for the following reaction: NH4Cl(s) → NH3(g) + HCl(g) Given the following standard enthalpies of formation ΔHf0 (298 K, 1 atm) NH3(g) -46.2 kJ mol-1 ; HCl(g) -92.3 kJ mol-1 ; NH4Cl(s) -315.0 kJ mol-1
step by step for both please T71 pts Consider the reaction: NH, (g) + HCI (9) ► NH,CI (s) Given the following table of thermodynamic data at 298 ok: Substance by admons Imoly NH HCI NHCI 4 6.19 -92.30 -314.4 192.5 186,69 94.6 The value of K for the reaction at 25°C is 150 1.4 x 10 1.1 x10-16 9.3 x1095 8.4 x109 Question 2 1/1 pts The equilibrium constant for the following reaction is 5.0 x 10% at 25°C....
Consider the reaction: FeO (s) + Fe (s) + O_2 (g) rightarrow Fe_2O_3 (s) Given the following table of thermodynamic data, Substance Delta H_f degree S degree FeO (S) -271.9 kJ/mol 60.75 J/mol - K Fe (s) 0 27.15 O_2 (g) 0 205.0 Fe_2O_3 (S) -822.16 89.96 determine the temperature (in degree C) above which the reaction is nonspontaneous.
Please do I do rate :) Consider the reaction NH4Cl(aq)-NH3(g) + HCl(aq) Using the standard thermodynamic data in the tables linked above, calculate the equilibrium constant for this reaction at 298.15K. ANSWER: