Question

Please answer the following question and show all work:

Problem 2: a) Consider the circuit below. If the potential of the battery is V = 120 V, determine the power consumption of each resistor. A 500 w 1003 $10009 D с b) You have three resistors with values 52, 10 92 and 152, respectively. Show how you would connect all three of them such that the equivalent resistance to be: i) 112 ii) 13.752 iii) 2.732

Answer 1

1 2 Can 1003 2120V loron 100 tl 1011 losso + lo loo looo 7 RE loro lou 9.900992 we get 50 9.90099 50+ 9.90099 NG V Reg= 59.90099

2. » 1: N Req 120 59.90099 a = 2.0033 50 2 in Power consumed consumed by Pso VI 2 그 RX 12 50 - 508 (2.0033) P 2 200.66 watt!

>> so PRO - 2.0033 x 50 100. 1653 v so .653 100.16539 -m V'= 120 - 100, 1653 120v = 19,8347 v => P = v'I' Y'V' Ric V Slovo I" Rio - 19.8347) 10 Pio = 39.34 Watt And P. (19.8347) ? 1) R1000 0.39 Walt

&o we have 39,34 Watt 10 Р. 200.66 Watt so Pooo = 0.39 Watt 262 s, 10, 10, 15 If we have all the three in parallel, then the equivalent resistance 5 her --М, 6 a 15 1 It is + 10 Re 6 + 3+ 2 30 30 > Rey 2.73 a N

So, all parellal give 2.732 ciig requirement that we need have Now left we day and s in series Is flo in parallel 10 ) b IS 10x IS 10tis 6 11 11 in senes with S : (10 llis) gines 112 = (id that we need

Now lety put in parelled s and is in seus and then get S 10 15 1) sxis 1 3.75 5+15 a 3.75 lo th 13.75 in senes with lo = ($1115) gines 13.75 R requirem rement