Homework Answers
Chromium carbonate : Cr2(CO3)3
molar mass : 2* 52 amu + 3* ( 12 + 3*16) = 284 g/mol
moles of Cr2(CO3)3: 179.3 g/ 284 g/mol = 0.6313 moles
moler ratio Cr2(CO3)3: C = 1 : 9
Thus moles of Carbon : 0.6313 mole Cr2(CO3)3* 9 mole C / Cr2(CO3)3 = 5.682 moles
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uploaded everything that was given. Where would I find the
experiemental values?
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