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11. (18 points on the replacement times for washing machines woman 3 years and standard deviation of 1.1 year. Find the proba


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Answer #1

(11)

Given \mu = 9.3

\sigma = 1.1

Less than 9.1:

P(X < 9.1) = ?

We know that the Standard Normal Variate is Z

Z = \frac{X - \mu }{\sigma }

\Rightarrow Z = \frac{9.1 - 9.3 }{1.1}

\Rightarrow Z = -0.1818

\Rightarrow Z = -0.18

Therefore P(X<9.1) = P(Z < -0.18) = ?

Therefore P(Z < -0.18) = ?

0.5 0.5 -0.18 Z = 0 -3 -2 -1 +1 +2 +3We have to find out the Probability of Shaded Area

\Rightarrow P( Z< -0.18) = P(-\infty <Z<-0.18)

\Rightarrow P( Z< -0.18) = P(-\infty <Z<0) - P(-0.18<Z<0)

\Rightarrow P( Z< -0.18) = 0.5 - 0.0714

\Rightarrow P( Z< -0.18) = 0.4286

The required Solution is 70x0.4286 = 30.002

NOTE:

P(-\infty <Z<0) = P(0 <Z<+\infty) = 0.5

To get the Value of P(-0.18 < Z <0) = P(0 < Z < +0.18);Search the Probability value which is intersected between the Z values 0.1 and 0.08; we will get 0.0714 in the standard normal tabulated value; which is posted below

Normal Distribution Table a 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.0000 0.0040 0.0080 0.0120 (0.0160 0.0199

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