Question

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Question 24 (1 point) A substance (A) reacts to form another substance (B): 3 A(9) 2 B(9) The reaction is run at a particular temperature with the concentrations of A and B monitored over time and plotted in the graph. At what time was equilibrium first reached and what is the approximate value of the equilibrium constant? 2.0 16 [B] LO concentration/M 10 IA] 04 00 • 30 20 x 50 60 90 100 110 120 130 140 150 time/min Equilibrium was reached at 30 min with Kc = 6. Equilibrium was reached at 30 min with Kc = 180. Equilibrium was reached at 70 min with Kc = 6. Equilibrium was reached at 70 min with Kc = 180. Question 25 (1 point) of

Answer 1

24) the equilibrium is the condition where the concentration of reactant and products remains constant (concentration does not change with time) in the graph after 70 min there is no change in concentration of reactant and products so it is time of equilibrium

At 70 min the conc of A is 0.2 M and concentration of B is 1.2 M. So for given equilibrium Kc= [B]² / [A]³ Kc = (1.2)² / (0.2)³ = 180

Si answer is the equilibrium is reached at 70 min and Kc is 180

22) BrO- is catalyst and reaction go through faster pathway   with BrO- than without  

23) we know Kc = [products] / [reactents]

As given value of Kc is very small value (1.1 x 10^-6) shows at equilibrium much higher the concentration of reactant is higher than products

24) I and II can be used to show that the reaction is first order