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Question 8 (1 point) Consider a system described by the equation 4 NO2 (g) + O2...
help me pleaseee Question 24 (1 point) A substance (A) reacts to form another substance (B): 3 A(g) = 2 B(8) The reaction is run at a particular temperature with the concentrations of A and B monitored over time and plotted in the graph. At what time was equilibrium first reached and what is the approximate value of the equilibrium constant? 2.0 16 IR [B] concentration/M 10 08 0.6 0.4 0.2 0.0 0 [A] 10 20 60 70 80 90...
Consider the equilibrium reaction at 100°C:2NO(g) + O2(g)⇌ 2NO2(g); KC = 30,000Write the concentration equilibrium equation for the reaction. If 46 grams of NO2(g) is introduced into a 1 L flask what will be the equilibrium concentrations of NO2, O2 and NO?
For the Equilibrium System N2 (g) + O2 (g) === 2 NO (g) 1.) Write a Kc and a Kp expression. 2.) If Kc = 1.50 x 10-2 at 653oC, Calculate and report the equilibrium concentrations of all of the reactants and all of the products at 653oC, if the initial concentrations were [N2]0 = 0.0100 M [O2]0 = 0.0200 M [NO]0 = 0.00300 M 3.) Calculate Kp for this equilibrium system at 653oC using the equation Kp = Kc(RT)∆n....
Consider the reaction below: N2O4 (g) → 2 NO2 (g) Which of the following techniques be used to determine the rate law is second order with respect to the concentration of dinitrogen tetroxide? O A graph of In([N204]) versus time will produce a straight line. A graph of [N204] versus time will produce a curved line. A graph of (N2O.) versus time will produce a straight line. The balanced chemical equation tells us that the reaction is first order with...
QUESTION 1 CH4(g) + 2 H2S(g) = CS2(g) + 4 H2(g) A reaction mixture initially contains 0.55 M CH4 and 0.53 M H2S. If the equilibrium concentration of H2 is 0.48 M, find the equilibrium constant (Kc) for the reaction. *Please report 3 significant figures. Numbers only, No unit. No scientific notation.
QUESTION 1 (10) Nitric oxide reacts with oxygen to form nitrogen dioxide: 2NO(g) + O2(g) + 2NO2 (g) a) What is the Kc for the reaction if the equilibrium concentration of NO is 0.300 M, O2 is 0.200 M, and NO2 is 0.530 M at 25°C? b) What is the Kp for the same reaction? c) If the equilibrium re-establishes where [NO]=0.150 M and [02]-0.225 M, what is [NO2) at this point under the same temperature? 2(12) The equilibrium constant...
please help me with the ones you can. thank you!! Solve for x in the equation: In = 10 1.3x10-4 Report your answer with 2 significant figures. A/ Question 2 (1 point) The decomposition of hydrogen peroxide is described below. 2 H2O2 (aq) → → 2 H2O (1) +O2 (g) rate = k[H202] The rate constant for the reaction is 5.3x10-4 M/s. If the initial concentration of hydrogen peroxide is 0.320 M, calculate the time it takes for the concentration...
please help as soon as possible ergent Question 24 (1 point) A substance (A) reacts to form another substance (B): 3 A(9) 2 B(9) The reaction is run at a particular temperature with the concentrations of A and B monitored over time and plotted in the graph. At what time was equilibrium first reached and what is the approximate value of the equilibrium constant? 2.0 16 [B] LO concentration/M 10 IA] 04 00 • 30 20 x 50 60 90...
1 2 Part A Calculate Kp at 298 K for the reaction NO(g) + + O2(g) → NO2 (g) assuming that AH is constant over the interval 298-600 K. Kp = 2.31x106 Submit Previous Answers ✓ Correct Part B Calculate Kp at 477 K for this reaction assuming that AHR is constant over the interval 298-600 K. PO AQ * o o ? Kp = | Submit Previous Answers Request Answer Revie For the reaction 2CH4 (g) = C2H2(g) +...
help me please asap Question 28 (1 point) What voltaic cell can be constructed to yield the most positive standard cell potential using the materials available in the table? 1/2 Reaction E° (V) Cu2+ + 2 e Cu +0.34 Cr3+ + 3 e Cr -0.41 Ag* + e → Ag +0.80 Cr|Cr3+(1.0 M)||Ag+(1.0 M)|Ag O Cr|Cr3+(1.0 M)||Cu2+(1.0 M)]Cu O CulCu2+(1.0 M)||Ag+(1.0 M)|Ag Ag|Ag+(1.0 M)||Cr3+(1.0 M)|Cr Question 27 (1 point) The formation of nitrogen trichloride is N2(g) + 3 C12(g) =...