Answer -
Given,
Initial Concentration Molarity of CH4 = 0.55 M
Initial Concentration of H2S = 0.53 M
Equilibrium concentration of H2 = 0.48 M
Kc = ?
CH4 (g) + 2 H2S (g) CS2 (g) + 4 H2 (g) [BALANCED]
Let us make the ICE table -
CH4 (g) in M | H2S (g) | CS2 (g) | H2 (g) | |
I | 0.55 | 0.53 | 0 | 0 |
C | -X | -2X | X | +4X |
E | 0.55-X | 0.53-2X | X | 4X |
It is given that,
Equilibrium Concentration of H2 (g) is 0.48 M
So,
4X = 0.48
X = 0.12 M
So,
Equilibrium Concentration of CH4 (g) = 0.55-0.12 = 0.43 M
Equilibrium Concentration of H2S (g) = 0.53-(2*0.12) = 0.29 M
Equilibrium Concentration of CS2 (g) = 0.12 M
Equilibrium Concentration of H2 (g) = 0.48 M
CH4 (g) + 2 H2S (g) CS2 (g) + 4 H2 (g) [BALANCED]
kc = [CS2][H2]4 / [CH4] [H2S]2
kc = (0.12)(0.48)4 / (0.43 ) (0.29)2
kc = 0.176 [ANSWER]
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