Question

A commercial steel pipe with inside diameter = 0.06 m and length = 40 m, the volumetric flow rate of liquid is 10 m3/h. Calculate the pressure drop if the friction factor = 0.0042. Density of liquid =1200 kg/m3. Select one: O a. 12662.72 N/m2 O b. 12960.51 N/m2 O c. 12556.77 N/m O d. 12997.81 N/m2 e. 11245.61 N/m2

Answer 1

The loss in pressure during fluid flow is due to:-

1) Fluid friction and turbulence

2) Change in fluid flow cross sectional area, and

3) Abrupt change in the fluid flow direction

Normally pressure drop due to fluid friction is called as major loss or frictional pressure drop ΔP

The loss Pressure loss during fluid flow :- in pressure during fluid froo 18 due to Fluid friction & Turbulence change in fluid flavo crass section area, and Abrupt change in the fluid foto flow direction Normally pressure doop due to fluid en friction is Called as Major loss ① fructional pressure drop (AP) Evalution of frictional pressure doop. when fluid flow through a pipe or a duch, the relative velocity of fluid at the wall of the pipe / duct will be zero, ecebo and this condition is known as No-slip condition The no-slip condition is met in most common fluid floro plom emosi As a result Velocity gradiant devloped inside the pipe / duct beganing with zero at the wall to a maximum Normally at the axis of conduit.. The velocity, greciaut give rise to Shear Stress ultimately resulting in frictional presser does The Darcy ---Weisbach oth equation is one of mosl- used equation for esti estimating frictional Pressure doof in internal flow. This equation is given by Darcy - Weisbach equation. + (y) L = lenth of bibe / Duct diameter of circulerduct Hycholic commonly AP = f = friction facter D = Se density V = Velocity in pipe/duct I diameter

Leuth of kipe 10 m3 5 + V= Qustion Answer Given → Inside diameater D = 0.06 m L = 40 m Discharge (volumetric flow rate) Q = 10 mln BOO friction factor f-0.0042 Density of liquid f= 1200 kg/m3 Formula Pressure doop [due to friction] – Darcy= (112) ** Q = AV where A = Crassection area of bike = AD² 42 4Q TD2 Darey-Wee's bach eah AP = f I A 2 14Q TD², 2 AP= = f. s Ś Calculation op = of L S Q² T2 D5 Ox IJ 0.0042 x 40 x 1200 x (10/3600) 2 x (106) Ap = 1621.509 N/m2 Ains