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Two capacitors have capacitances of 5.0 pF and 3.5 pF. Initially, the first one has a potential difference of 13.0 V and the

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Given, C,= 5.0 MF C2 = 3.5 4F Vi= 13.0V V2=8.0v @=cv Equivalent Capecitance Ceq=C, tcz Ceq = 8.5 MÅ Q = Civit Cz V2 =) Q = 65

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