Question

The following problem is not multiple choice. Final numerical answer is not sufficient to get full credits on the problem. You need to explain what you did and what you used to get your answers. a stone is projected at a cliff of height h with an initial speed of 46 m/s directed at angle 00 = 60.0° above the horizontal. The stone strikes at A, 6s after launching. Find (a) the height h of the cliff, (b) the speed of the stone just before impact at A, and (c) the maximum height H reached above the ground. H E ESCO PA 80

Answer 1

Ans. Initial speed, u= 46 m/s Angle of projection, 9. = 60 (0) ) Maximum height reached, H = 2 2 usin lo 2 9 (46) sin (60) 249.8 =180.97 m 2g ta 4.07 sec g 6 -4.07 5 2 . (a) vertical component component of initial velocity u Sin Oo 39.84 m Velocity at heighest point, bro a sindo Using using=(-ght time taken to reach heighest point, t= 4:07 sec time of fall 1.93 sec Distance of fall sa ut +Lat u= velocity at highest point =0 m/s (9.8) (1.93 height of cliff 80.97-18.25 62.72 m Vertical co component of velocity at A, Oy 9.8 x1.93-18.9 m/s Horizontal a pa uloso = 23 m/s velocity at point A, V = 1 + uz - 29.8 mis 2 S = 8 18.25 m 2 )